Well, I think when we need just the two minimum items in the list, there is not optimal to sort all the list and then just pick two of them. ---> O(n^2) >> O (2n)

How is telling you which data structure to use a spoiler?
Well, if I tell you about the streamlined algorithm, then that is a spoiler. There is a loop within loop way, and there is a way to do this with one loop.

Please use new python test framework.

Looks like u solved it

Looks like u solved it

looks like u alr solved it

Sure, it is, I just mean that to find the first two min of the list, (2n) in enough instead of (n^2) or (n log n)

There is no such thing as O(2n). The 2 drops out since it's a constant, so it's actually O(n).

Yes, if they are implemented in quick-sort or heap-sort or... .Also O(n log n) > O(2n)

sorting is

`O(n log n)`

, not`O(n²)`

(out of special considerations, and assuming you're using a builtin to do it)Well, I think when we need just the two minimum items in the list, there is not optimal to sort all the list and then just pick two of them. ---> O(n^2) >> O (2n)

How is telling you which data structure to use a spoiler?

Well, if I tell you about the streamlined algorithm, then that is a spoiler. There is a loop within loop way, and there is a way to do this with one loop.

what is a streamlined algorithm?

You should have marked your comment as spoiler.

This comment is hidden because it contains spoiler information about the solution

As far as I can see, it's shown in the description.

Hi all

where can I find the Fighter class at codewars?

i have solved this task on Intellij without any problems but not here on codewars.

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